X^2-2x-0.6=0

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Solution for X^2-2x-0.6=0 equation: 



X^2-2X-0.6=0

a = 1; b = -2; c = -0.6;
Δ = b2-4ac
Δ = -22-4·1·(-0.6)
Δ = 6.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-\sqrt{6.4}}{2*1}=\frac{2-\sqrt{6.4}}{2}
$


$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+\sqrt{6.4}}{2*1}=\frac{2+\sqrt{6.4}}{2}
$

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